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转载:https://www.jb51.net/article/172623.htm iteritems():按列遍历,将DataFrame的每一列迭代为(列名, Series)对,可以通过row[index]对元素进行访问。 示例数据 1 2 3 4 5 6 import pandas as pd
inp = [{'c1':10, 'c2':100}, {'c1':11, 'c2':110}, {'c1':12, 'c2':123}] df = pd.DataFrame(inp)
print(df) import pandas as pd inp = [{'c1':10, 'c2':100}, {'c1':11, 'c2':110}, {'c1':12, 'c2':123}] df = pd.DataFrame(inp) print(df) 按行遍历iterrows(): 1 2 for index, row in df.iterrows(): print(index) # 输出每行的索引值 for index, row in df.iterrows(): print(index) # 输出每行的索引值 row[‘name'] 1 2 3 # 对于每一行,通过列名name访问对应的元素 for row in df.iterrows(): print(row['c1'], row['c2']) # 输出每一行 # 对于每一行,通过列名name访问对应的元素 for row in df.iterrows(): print(row['c1'], row['c2']) # 输出每一行 按行遍历itertuples(): getattr(row, ‘name') ? 1 2 for row in df.itertuples(): print(getattr(row, 'c1'), getattr(row, 'c2')) # 输出每一行 for row in df.itertuples(): print(getattr(row, 'c1'), getattr(row, 'c2')) # 输出每一行 按列遍历iteritems():
1 2 for index, row in df.iteritems(): print(index) # 输出列名 for index, row in df.iteritems(): print(index) # 输出列名
1 2 for row in df.iteritems(): print(row[0], row[1], row[2]) # 输出各列 for row in df.iteritems(): print(row[0], row[1], row[2]) # 输出各列
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